So, as you may know harmonic series implies:
In this program, we take the integer value of n from the user and display the sum of the series according to this value. I just used a for loop, although there are many other ways to do the same.
Here is the code:
Here is the output:
Happy Coding!
:)
In this program, we take the integer value of n from the user and display the sum of the series according to this value. I just used a for loop, although there are many other ways to do the same.
Here is the code:
#include <stdio.h> #include <conio.h> int main() { int n,i; float inverse; double sum=0.0; //Preliminary printf(\"Program to find:\\n\"); printf(\"\\n 1 1 1 1 1\\n\"); printf(\" __ + __ + __ + __ + ... + __\\n\"); printf(\"\\n 1 2 3 4 n\\n\"); //Prompting for the value for 'n' printf(\"\\n\\nEnter the value of n: \"); scanf(\"%d\", &n); //Iterating and summing for(i=1; i<=n; i++) { inverse = (1.0/i); sum += inverse; } //Displaying the answer printf(\"\\nRequired sum is %f\", sum); getch(); return 0; }
Here is the output:
Happy Coding!
:)
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