Here is the C++ program to find out whether a give number is odd or even :
The program works on the simple logic that the remainder of an even number when divided by 2 is 0 and that of an odd number is 1.
/*Please support me by commenting and subscribing and viewing my blog frequently! - GeekyCircle Admin */ #include<iostream.h> #include<conio.h> void main() { int num; cout<<"Enter the number to be processed : "<<endl; cin>>num; if(num%2==0) { cout<<"The number is even!"; } else if(num%2==1) { cout<<"The number is odd!"; } getch(); }
For newer IDEs (like Dev C++) :
/*Please support me by commenting and subscribing and viewing my blog frequently! - GeekyCircle Admin */ #include<iostream> using namespace std; int main() { int num; cout<<"Enter the number to be processed : "<<endl; cin>>num; if(num%2==0) { cout<<"The number is even!"; } else if(num%2==1) { cout<<"The number is odd!"; } return 0; }Here is the video tutorial of this program :
The program works on the simple logic that the remainder of an even number when divided by 2 is 0 and that of an odd number is 1.
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