Here is the C++ program to find out whether a give number is odd or even :
The program works on the simple logic that the remainder of an even number when divided by 2 is 0 and that of an odd number is 1.
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#include<iostream.h>
#include<conio.h>
void main()
{
int num; cout<<"Enter the number to be processed : "<<endl;
cin>>num;
if(num%2==0)
{
cout<<"The number is even!";
}
else if(num%2==1)
{
cout<<"The number is odd!";
}
getch();
}
For newer IDEs (like Dev C++) :
/*Please support me by commenting and subscribing and viewing
my blog frequently! - GeekyCircle Admin */
#include<iostream>
using namespace std;
int main()
{
int num; cout<<"Enter the number to be processed : "<<endl;
cin>>num;
if(num%2==0)
{
cout<<"The number is even!";
}
else if(num%2==1)
{
cout<<"The number is odd!";
}
return 0;
}
Here is the video tutorial of this program : The program works on the simple logic that the remainder of an even number when divided by 2 is 0 and that of an odd number is 1.
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