"Find the sum of n numbers input by the user using classes in C++"This is an important question which has high probability to be asked in CBSE/Other states Computer Science practical examinations. This question is also important because it uses most of the basic concepts of C++ like iteration, arrays, classes, etc; Hence I have decided to share this program with you. It is fairly simple if you have a little logic and also know about classes in C++.
Here is the code :
/*Support us by subscribing, commenting, and viewing the blog frequently! -GeekyCircle Admin :)*/ #include<iostream.h> #include<conio.h> class sumNumbers { int counter,num_of_num,num_array[100], sum; public: void input() { cout<<"How many numbers? : "; cin>>num_of_num; cout<<"\nEnter the numbers : "<<endl; //Part one for (counter = 0; counter < num_of_num; counter++) { cin>>num_array[counter]; } cout<<"\nThe numbers given are : "<<endl; for (counter = 0; counter < num_of_num; counter++) { cout<<num_array[counter]<<"\t"; } } void process() { //Part two - This is where the magic happens! sum = 0; for(counter = 0; counter < num_of_num; counter++) { sum = sum + num_array[counter]; } } void output() { cout<<"\n\nRequired sum is "<<sum<<endl; } }; void main() { //Part Three sumNumbers object; object.input(); object.process(); object.output(); getch(); }
For newer IDEs, visit this page.
Working
Let us assume that user wants the sum of seven numbers from 1 to 7 (1, 2, 3, 4, 5, 6, 7)
Remember that 1 does not have the position [1], but [0] as in any array.
Graphical representation of the example array |
- Part One
- First the number of numbers to be added is asked. It is identified by the variable 'num_of_num'
- Now we ask to enter the numbers. These numbers are assigned to an array, in this case, 'num_array'
This array is input using a for loop. The input numbers are showed to the user using another for loop. - The numbers, 1, 2, 3, 4, 5, 6, 7 are now in an array.
2. Part Two
- A variable 'sum' is initialized and is assigned a value 0. And counter is initially at 0.
- num_array[0] is 1. Hence sum becomes sum + num_array[0] = 0 + 1 = 1
- counter is incremented to 1. num_array[1] is 2. Hence sum becomes sum (which is now 1) + num_array[1] = 1 + 2 = 3.
- This process is continued till counter since we have the expression counter < n. The last step is :
sum = sum + num_array[6] = 21 + 7 = 28 - loop is then terminated and the final value of sum is 28. So the program outputs 28.
3. Part Three
- Nothing much here... Just the main function. An object of the class sumNumbers, is declared, with a name 'object'.
- All the member functions, input, process and output are called!
That's it for now guys... Please continue to support us. Later...
No comments:
Post a Comment